Arrhenius Equation

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A2 Inorganic Chemistry
A few notes I've made on Arrhenius.

Arrhenius Equation

Exponential relationship between the rate constant (k) for a reaction and temperature.

Determining Activation Energy (Ea) from experimental data
This relationship can be used to determine Ea graphically.

Experimental data containing the value of k at various temperatures can be plotted as ln(k) against 1/T in Kelvin to produce a linear function with negative gradient. The gradient shall be equal to -(Ea)/R where R is the molar gas constant (R = 8.314 J mol^-1 K^-1), so by rearranging, the activation energy for a reaction (in J) can be calculated.

TL;DR
fLXcoQ0.png
 
If this is chemistry, I'll stick with Physics thanks.

Physics consists of a load of maths and problem solving, both of the things I like and understand
 
A2 Inorganic Chemistry
A few notes I've made on Arrhenius.

Arrhenius Equation

Exponential relationship between the rate constant (k) for a reaction and temperature.

Determining Activation Energy (Ea) from experimental data
This relationship can be used to determine Ea graphically.

Experimental data containing the value of k at various temperatures can be plotted as ln(k) against 1/T in Kelvin to produce a linear function with negative gradient. The gradient shall be equal to -(Ea)/R where R is the molar gas constant (R = 8.314 J mol^-1 K^-1), so by rearranging, the activation energy for a reaction (in J) can be calculated.

TL;DR
fLXcoQ0.png

If this is chemistry, I'll stick with Physics thanks.

Physics consists of a load of maths and problem solving, both of the things I like and understand

Are you serious? 99% of this is physics and maths. Having to rearrange the equation y=mx+c with a straight line graph to make a new equation is physics. You can be asked this in most physics topics that i'm doing and i have to use it in my practical work. Only thing that's different is what each term means.
 
Last edited:
A2 Inorganic Chemistry
A few notes I've made on Arrhenius.

Arrhenius Equation

Exponential relationship between the rate constant (k) for a reaction and temperature.

Determining Activation Energy (Ea) from experimental data
This relationship can be used to determine Ea graphically.

Experimental data containing the value of k at various temperatures can be plotted as ln(k) against 1/T in Kelvin to produce a linear function with negative gradient. The gradient shall be equal to -(Ea)/R where R is the molar gas constant (R = 8.314 J mol^-1 K^-1), so by rearranging, the activation energy for a reaction (in J) can be calculated.

TL;DR
fLXcoQ0.png


Yes
 
Explain this again, but use some drugs examples instead of those graphs and you'll get 80% more people that'll understand this.
 
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